I have a titration problem I am having trouble with...?

Convert the volume of NaOH into liters, and multiply that by the molarity...That gives you moles of NaOH. Tartaric acid has 2 carboxyl groups, doesn't it? (You'll need to check that, if you don't know for sure...). uming that it does, then 2 moles of NaOH will be required to react with 1 mole of tartaric acid. So, dividing the moles of NaOH by 2 gives you the moles of tartaric acid. Finally, divide the moles of tartaric acid by the volume you used (15 mL) also expressed in Liters, and you have the molarity of the tartaric acid solution.